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A 20g sample of a hydrate of nickle sulphate (NiSO4) lost 9.63g of water when heated. Determine the hydrate formula. 解き方がわかりません お願いします
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硫酸ニッケル(NiSO4)の水和物20gを加熱したら9.63gの水分を失った。水和物の化学式を求めよ。でしょうか。 化学式を、NiSO4・xH2O とする。 式量は、 58.7+32.1+4*16+x*18=154.8+x*18 全部で20g、水分が9.63gだから、 (x*18)/(154.8+x*18)=9.63/20 x=9.63*154.8/(18*(20-9.63))=7.99 だから、 NiSO4・8H2O か。 だけど、NiSO4の水和物は、ふつうNiSO4・6H2O かNiSO4・7H2O だったような気がする。どっか間違ってるかな。
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