heterodetic ringとは？？？
- heterodetic ringとは、インスリンのAチェーン内に形成されるヘテロデティックリングのことを指します。
- インスリンはAチェーンとBチェーンからなり、半シスチン残基間に形成される3つのジスルフィド結合が存在します。
- ヘテロデティックリングはAチェーン内のA6とA11の位置を結びつけ、インスリンの構造上の重要な要素となっています。
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heterodetic ringとは？？？
heterodetic ring とはどう訳せばいいのか教えてください！ いろいろな文節で区切って考えてみましたがわかりませんでした。 もしかしてこれは日本語訳がないのですか？ できれば、どんなものか補足してくれる方がいればうれしいです！ ちなみにインスリンの説明文ででてきました！ 参考までにその文の一部を載せます！(訳してほしいわけではないです！heterodetic ringがわかればいいです！) The sequences of a large number of insulins are now known, all of which consist of two polypeptide chains, commonly termed the A chain and the B chain, with three disulfide bridges formed between half-cystine residues; two of three bridges are interchain, forming A7-B7 and A19-A20 links, and the third is intrachain, linking positions A6 and A11 to form a heterodetic ring in the A chain. The number of amino-acid residues vary slightly with the species of origin, commonly being 21 and 30 in the A and B chains, respectively; six amide groups are present per molecule of the monomer if insulin is carefully isolated. お願いします！！
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heterodetic peptideとは、アミノ酸残基間にペプチド結合以外の共有結合もあるペプチドのこと。それによってリングになっていれば…ということでしょう。日本語訳はわかりません。 せっかくネットを使えるんですから、日本語圏の辞書になければ英語圏の辞書を使ってみるということもできますよ。
関連するQ&A
- 生物論文の和訳
下記の論文を訳してください。 1)We wish to put forward a radically different structure for the salt of deoxyribose nucleic acid.This structure has two helical chains cach colied round the same axis(see diagram).We have made the usual chemical assumptions,namely,that each chain consists of phophates di-ester groups joining B-D-deoxy-ribofuranose residues with 3',5' linkages.The two chains (but not their bases) are related by a dyad perpendicular to the fibreaxis.Both chains follow right-handed helices,but owing to the dyad the sequences of the atoms in the two chains run in opposite directions.Each chains loosely resembles Fur-berg's model No.1 ; that is,the bases are on the inside of the helix and the phophates on the outside.The configuration of the sugar and the atoms near it is close to Furberg's 'standard configuration',the sugar being roughly perpendicular to the attached base.
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- 生物学
- 和訳してください!!(前半)
Molecular Structure Of Nucleic Acids A Structure for Deoxyribose Nucleic Acid We wish to suggest a structure for the salt of deoxyribose nucleic acid (D.N.A.). This structure has novel features which are of considerable biological interest. A structure for nucleic acid has already been proposed by Pauling and Corey (1). They kindly made their manuscript available to us in advance of publication. Their model consists of three intertwined chains, with the phosphates near the fibre axis, and the bases on the outside. In our opinion, this structure is unsatisfactory for two reasons: 1) We believe that the material which gives the X-ray diagrams is the salt, not the free acid. Without the acidic hydrogen atoms it is not clear what forces would hold the structure together, especially as the negatively charged phosphates near the axis will repel each other. 2) Some of the van der Waals distances appear to be too small. Another three-chain structure has also been suggested by Fraser (in the press). In his model the phosphates are on the outside and the bases on the inside, linked together by hydrogen bonds. This structure as described is rather ill-defined, and for this reason we shall not comment on it. We wish to put forward a radically different structure for the salt of deoxyribose nucleic acid. This structure has two helical chains each coiled round the same axis (see diagram). We have made the usual chemical assumptions, namely, that each chain consists of phosphate diester groups joining ß-D-deoxyribofuranose residues with 3',5' linkages. The two chains (but not their bases) are related by a dyad perpendicular to the fibre axis. Both chains follow right-handed helices, but owing to the dyad the sequences of the atoms in the two chains run in opposite directions. Each chain loosely resembles Furberg’s (2) model No. 1; that is, the bases are on the inside of the helix and the phosphates on the outside. The configuration of the sugar and the atoms near it is close to Furberg’s ‘standard configuration’, the sugar being roughly perpendicular to the attached base. There is a residue on each chain every 3.4 A. in the z-direction. We have assumed an angle of 36° between adjacent residues in the same chain, so that the structure repeats after 10 residues on each chain, that is, after 34 A. The distance of a phosphorus atom from the fibre axis is 10 A. As the phosphates are on the outside, cations have easy access to them. This figure is purely diagrammatic. The two ribbons symbolize the two phosphate-sugar chains, and the horizontal rods the pairs of bases holding the chains together. The vertical line marks the fibre axis.
- 締切済み
- 英語
- 生物論文を和訳２
下記の英文を訳してください 1)There is a residue on each chain every 3・4 A.in the z-direc-tion.We have assumed an angle of 36゜ between structure repeats after 10 residues on each chain,that is,after 34 A. The distance of a phophates atom from the fibre axis is 10 A. As the phophates are on the outside,cations have easy access to them. 2)The structure is an open nne,and its water contents we would expect the bases to tilt so that the structure could become more compact. 3)The novel feature of the structure is the manner in which the two chains are held together by the purine and pyrimidine bases.The planes of the bases are perpendicular to the fibre axis.They are joined together in pairs,a single base from one chain being hydrogen-bonded to a single bases from the other chain,so that the two lie side by side with identical z-co-ordinates.One of the pair must be a purine and the other a pyrimidine for bonding to occur.
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- 日本語に訳してください
In a set of four numbers, the first three are in an arithmetic sequence with a common difference of -12 and the last three are in a geometric sequence. Provided the first number equals the fourth, find the four numbers. 数学についての英文です。 よろしくお願いします。
- ベストアンサー
- 英語
- 生物論文の和訳
下記の論文を訳してください 2)The structure is an open nne,and its water contents we would expect the bases to tilt so that the structure could become more compact. 3)The novel feature of the structure is the manner in which the two chains are held together by the purine and pyrimidine bases.The planes of the bases are perpendicular to the fibre axis.They are joined together in pairs,a single base from one chain being hydrogen-bonded to a single bases from the other chain,so that the two lie side by side with identical z-co-ordinates.One of the pair must be a purine and the other a pyrimidine for bonding to occur.
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- 英語
- acrossかoverか
Durham is a historical city in the north-east of England. There is an eleventh century Norman cathedral and there is also a majestic castle. There are three old stone bridges across the river and there is a very famous university. 質問です。three old stone bridges across the riverの部分ですが、acrossの代わりにoverも使えると思いますが、どっちが普通の言い方でしょうか？
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- その他（語学）
- この文章の和訳を教えてください。
3.1. Case of e=0 and i=0 We have first calculated 6000 orbits in the parameter range of b from b_min=1.9 to b_max=2.5 at intervals of 0.0001. It is already known from previous studies (Nishida, and Petit and Hénon) that no collision orbits exist outside this region. The orbits vary in a complicated way with the value of parameter b (see Petit and Hénon, 1986). In spite of the complex behavior of the orbits, we can classify them in terms of the number of encounters with the two-body sphere, from the standpoint of finding collision orbits. The classes are: (a) non-encounter orbit, (b) n-recurrent non-collision orbit, and (c) n-recurrent collision orbit, where the term “n-recurrent orbit” means the particle encounters n-times with the two-body sphere. That is, n-recurrent non-collision (or collision) orbits are those which fly off to infinity (or collide with the protoplanet ) after n-times encounters with the two-body sphere, while non-recurrent orbits are those which fly off without penetrating the two-body sphere. Examples of orbits in the classes (a), (b), and (c) are illustrated in Figs. 2,3, and 4, respectively. The above classification of orbits will be utilized for developing numerical procedures for obtaining <P(e, i)>, as described in the next section. よろしくお願いします。
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- この文章の和訳をよろしくお願いします。
3. Examples of orbital calculations To find efficient numerical procedures for obtaining <P(e ,i)>, we have made detailed orbital calculations for two typical cases, (e, i)=(0, 0) and (1, 0.5). The former is the simplest case with a single parameter b, and corresponds to that studied by Giuli (1968), Nishida (1983) and Petit and Hénon (1986). In the latter, the orbit changes with three parameters b, τ, and ω in a complicated manner. From this example, we can see the characteristic features of orbits in the three-dimensional case. In the present examples, it is supposed that a protoplanet with a mean mass density 3gcm^-3, orbits in the Earth’s region. Furthermore, we adopt 1% as the limiting accuracy criterion for use of the two-body approximation. These give 0.005 and 0.03 for the radius of the protoplanet and that of the two-body sphere, respectively (see Eqs. (12) and (13)). よろしくお願いします。
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- TOEFLの文法問題
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ありがとうございました☆