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この問題の解き方と答えをおしえてください。 問題文が英語になってしまいますがよろしくおねがいします。 The height h, in meters, at some time t, in seconds, of an object propelled upward at a speed of 82 meters per second from an initial height of 103 meters is given by the function h(t)=-10t^2+82t+103. a) What is the maximum height of the object? b) When will the object be above 200 meters high? c) When will the object hit the ground?

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a) h(t)=-10(t^2-8.2t)+103=-10(t-4.1)^2+103+168.1 ==-10(t-4.1)^2+271.1 the maximum height is 271.1(meter) b) h(t)=-10t^2+82t+103=200 10t^2-82t+97=0 t=(82±(82^2-4*10*97)^0.5)/2/10=1.435, 6.765 1.43<t<6.77(sec) c)h(t)=-10t^2+82t+103=0 t>0, t=9.31(sec)

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