数学問題です

質問

最終3枚目の質問です。
宜しくお願いします。

回答No.1

info33

(1 )
log(2) 2√6 -log(2)√3=log(2) 2√6/√3=log(2) 2√2=log(2)2^(3/2)=(3/2)log(2)2=3/2
(2)
2log(2)√2-(1/2)log(2)3+log(2) {√3/2}=log(2)2-log(2)√3+log(2) {√3/2}
=log(2)2-log(2)√3 +log(2)√3 -log(2) 2 =0
(3)
log(4)5 * log(5)8=log(4)5 * log(5)8={log(5)2^3}/{log(5)2^2}=3/2
(4)
log(2)6 -log(4)9=log(2)6 -log(2)3 =log(2)(6/3)= 1
(5)
log(5)75-log(25)9=log(5)(25*3)-log(5)3=2+log(5)3-log(5)3= 2